functx:sequence-node-equal-any-order
Whether two sequences contain the same XML nodes, regardless of order
Description
The functx:sequence-node-equal-any-order function returns a boolean value indicating whether the two arguments have the same nodes, in any order. They are compared based on node identity, not their contents.
Parameters |
Description |
|---|---|
seq1:node() |
the first sequence of nodes |
seq2:node() |
the second sequence of nodes |
Examples
The examples below use this input document:
<xsl:variable name="in-xml" as="item()*">
<authors>
<author>
<fName>Kate</fName>
<lName>Jones</lName>
</author>
<author>
<fName>John</fName>
<lName>Doe</lName>
</author>
</authors>
</xsl:variable>
<xsl:variable name="anAuthor" as="item()*">
<author>
<fName>Kate</fName>
<lName>Jones</lName>
</author>
</xsl:variable>
XPath |
Results |
|---|---|
functx:sequence-node-equal-any-order($in-xml/author, $in-xml/*) |
true |
functx:sequence-node-equal-any-order($in-xml/author, ($in-xml/author[2],$in-xml/author[1])) |
true |
functx:sequence-node-equal-any-order($in-xml/author[1],$anAuthor) |
false |